js获取url中的参数
var getURLParam = function(name) {
return decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)', "ig").exec(location.search) || [, ""])[1].replace(/\+/g, '%20')) || null;
};
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var getURLParam = function(name) {
return decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)', "ig").exec(location.search) || [, ""])[1].replace(/\+/g, '%20')) || null;
};
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